def main(): print("Pangya Hole-in-One Calculator 2021") distance = float(input("Enter distance to hole (yards): ")) club_power = float(input("Enter club power (yards): ")) wind_direction = input("Enter wind direction (headwind/tailwind/crosswind): ").lower() wind_strength = float(input("Enter wind strength (yards): "))
Then, have a main function that loops for the user to enter data. holeinonepangyacalculator 2021
def calculate_hole_in_one_chance(distance, club_power, wind_effect, accuracy, skill_bonus): effective_distance = distance + wind_effect power_diff = abs(club_power - abs(effective_distance)) base_chance = max(0, (100 * (1 - (power_diff2)))) * accuracy) adjusted_chance = base_chance * (1 + skill_bonus) return min(100, adjusted_chance) In reality, in many games, the probability of
But since the user wants a 2021 version, perhaps there's an update in the game's mechanics compared to previous years. However, without specific info, I'll proceed with a plausible formula. But this is just an example
In reality, in many games, the probability of a Hole-in-One might be determined by certain stats. For example, maybe the player's accuracy, the strength of the club, the distance to the hole, terrain modifiers, etc. So the calculator could take these inputs and compute the probability.
But this is just an example. The actual calculator would need to accept inputs for D, P, W, A, S and compute the probability.